Question

Show that p(x) =
x ²- 3 x ² + 2 + 6 has only
one real zero
​

Answer 1

Answer:

p(x) = x²-3x²+2+6=0

=> -2x²+8=0

=> -2x² = -8

=> 2x² = 8

=> x² = 8/2

=> x² = 4

=> x = √4

=> x = 2