show that p(x)=x^3-3x^2+2x-6 has only one real zero
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answer is 3
esitimating the value be 3
x=3
x3- 3x2 +2x-6
(3*3*3)-3*3*3+2*3-6
27-27+6-6
0
hence the value of x is 3
esitimating the value be 3
x=3
x3- 3x2 +2x-6
(3*3*3)-3*3*3+2*3-6
27-27+6-6
0
hence the value of x is 3
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