Question

Show that p(x)=x^3-3x^2+2x-6 has only one real zero​

Answer 1

Step-by-step explanation:

f(x)=x

3

+3x

2

−2x−6

Let the third Zero be α

α+

2

+(−

2

)=−3

α=−3

So all the zeros of f(x) are

2

,−

2

,−3