Question

show that p(x)=x^3-5x^2+4x-3 us not the multiple of g(x)=x-2​

Answer 1

Answer:

p(x) =x^3-5x^2+4x-3

g(x) =x-2

Let g(x) =0

=> x-2=0

=>x=2

•°• p(2) =2^3-5(2)^2+4(2)-3

=8-20+8-3

=16-23

=-7

As p(x) is not equal to zero

•°• g(x) is not the factor of p(x).