show that p(x)= x cube - 3x square + 2x -6
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Since p(a)= P( b)= P(C)= 0 ...a, b, c are the zeroes of the given polynomial
→(2-a)(2-b)(2- c)
→8 -4(a+ b+ c)+ 2( ab+ bc+ ca)- abc ... ...( i)
We know that sum of zeroes= a+b+c= -B/ A=- - 3/ 1=3
:ab+ b c+ ca= C/ A=2
abc=-D/A=-5
Putting the above values in (i)
Ans comes as +5
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