Question

show that p(y) = y^2 + 6y + 18 has no zero.
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Answer 1

Step-by-step explanation:

y^2 + 6y + 18

= y^2 + 6y - 3y +18

= y( y + 6) - 3( y + 6)

= (y-3) (y+6)

y-3=0 y+6=0

y=3 y=-6