Math, asked by at495717, 1 month ago

Show that pair of equations 3x-5y=20 and 6x-10y=-40 has no solution.​

Answers

Answered by sumanman5431
0

Answer:

don't know can anyone tell please

Answered by STATUZ
1

Given, 3x – 5y = 20……. (i) 6x – 10y = – 40……. (ii) For equation (i), ⇒ y = (3x–20)5(3x–20)5 When x = 5, we have y = (3(5)–20)5(3(5)–20)5 = -1 When x = 0, we have y = (3(0)–20)5(3(0)–20)5 = -4 Thus we have the following table giving points on the line 3x – 5y = 20 x 5 0 y -1 -4 For equation (ii), We solve for y: ⇒ y = (6x+40)10(6x+40)10 So, when x = 0 y = (6(0)+40)10(6(0)+40)10 = 4 And, when x = -5 ⇒ y = (6(-5) + 40)/10 = 1 Thus we have the following table giving points on the line 6x – 10y = – 40Read more on Sarthaks.com - https://www.sarthaks.com/624317/show-graphically-the-systems-equations-is-in-consistent-has-no-solution-3x-5y-20-6x-10y-40?show=624426#a624426

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