Question

show that parallelogram on the same base and between the same parallels are equal in area.​With diagram. No fake answers please

Answer 1

in tri ABC n tri DEF

AB =DE(OPP SIDES OF PRLLGRM

angle bca=angle efd(corresponding)

ANGLE bac=angle edf(corresponding angles)

By AAS tri abc is congruent to tri def

and congruent tri have equal area

so

ar ABC=ar DEF

adding ar BCDE

ar ABC + BCDE= ar DEF+ BCDE

ar BADE = ar BCFE

hp