show that parllelogram and rectangle on same base and between same parllels have equal area
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parrallograms and rectangles on same base and between same parallels are equal in area.
In the adjoining figure, parallelogram ABCD and rectangle ABEF are on the same base BC and between the same parallels AB and l.
Parallelograms and Rectangles on Same Base and between Same Parallels
Therefore, area of parallelogram ABCD = Area of rectangle ABEF
= AB × AF
AF is also the altitude of the parallelogram.
Hence, area of the parallelogram = base × height
= AB × AF
In the adjoining figure, parallelogram ABCD and rectangle ABEF are on the same base BC and between the same parallels AB and l.
Parallelograms and Rectangles on Same Base and between Same Parallels
Therefore, area of parallelogram ABCD = Area of rectangle ABEF
= AB × AF
AF is also the altitude of the parallelogram.
Hence, area of the parallelogram = base × height
= AB × AF
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Percyjackson101:
Thx dhruv
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