Question

show that pH + poh equal to 14 for any aqua solution at 25 degree Celsius

Answer 1

hey buddy❤❤❤❤

here's ur answer==>>

given== Kw(disassociation constant)= $10^{-14}$

since Kw= $H^{+}$$H^{+}$

apply log..

log $10^{-14}$= log$H^{+}$$OH^{-}$

-14 = log$H^{+}$+log$OH^{-}$

multiply by (-) on both sides...

14= -log$H^{+}$-log$H^{+}$

pH + pOH = 14 ...

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