Math, asked by shaikhshabrin454, 1 year ago

Show that point (0,9) is equidistant from the point (-4,-1) and(4,1)​

Answers

Answered by ayushtripathi70
1

Answer:

here your answer but I am not sure so it is 50 50

Attachments:
Answered by dk6060805
13

Point (0,9) is equidistant

Step-by-step explanation:

distance between point (0 , 9) & (-4 , -1) is

= \sqrt{(0 - (-4)^2) + (9 - 1)^2}

= \sqrt {4^2 + (8)^2}

= \sqrt{80}""""(1)

Now, distance between point (0 , 9) & (4 , 1)

= \sqrt{(0 - (4))^2 + (9 - 1)^2}

= \sqrt{16 + 64}

= \sqrt {80} """"(2)

From (1) & (2) we get:

Both are equal or

Point (0,9) is equidistant from the point (-4,-1) and(4,1)​

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