Question

show that point (2,4) (3,0) and (9,0) are the vertices of right angled isosceles triangle

plz solve this problem ​

Answer 1

Step-by-step explanation:

Let A(x1,y1)=(3,2),B(x2,y2)=(2,−3) and C(x3,y3)=(0,0)

∴ Distance between two points  =(x2−x1)2+(y2−y1)2

AB=(2−3)2+(−3−2)2=1+25=26units

BC=(0−2)2+(0+3)2=4+9=13units

CA=(0−3)2+(0−2)2

Answer 2

Let A(x1,y1)=(3,2),B(x2,y2)=(2,−3) and C(x3,y3)=(0,0)

∴ Distance between two points  =(x2−x1)2+(y2−y1)2

AB=(2−3)2+(−3−2)2=1+25=26units

BC=(0−2)2+(0+3)2=4+9=13units

CA=(0−3)2+(0−2)2