show that points A(-4,-7),B(-1,2),C(8,5) and D(5,-4) are the vertices of a parallelogram ABCD.
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Answered by
5
Answer:
Step-by-step explanation:
The given points are A(-4, -7), B(-1, 2), C(8, 5) and D(5, -4).
Slope of AB =
−1−(−4)
2−(−7)
=
3
9
=3
Slope of BC =
8−(−1)
5−2
=
9
3
=
3
1
Slope of CD =
5−8
−4−5
=
−3
−9
=3
Slope of AD =
5−(−4)
−4−(−7)
=
9
3
=
3
1
Slope of AB = Slope of CD
Slope of BC = Slope of AD
So, AB II CD and BC II AD
Hence, ABCD is a parallelogram.
Answered by
1
Answer:
The given points are A(-4, -7), B(-1, 2), C(8, 5) and D(5, -4).
Slope of AB =
−1−(−4)
2−(−7)
=
3
9
=3
Slope of BC =
8−(−1)
5−2
=
9
3
=
3
1
Slope of CD =
5−8
−4−5
=
−3
−9
=3
Slope of AD =
5−(−4)
−4−(−7)
=
9
3
=
3
1
Slope of AB = Slope of CD
Slope of BC = Slope of AD
So, AB II CD and BC II AD
Hence, ABCD is a parallelogram.
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