Question

show that points p(2,-2), Q(7,3), R(11,-1) and S(6,-6) are vertices of a parallelogram​

Answer 1

Step-by-step explanation:

The given points are

P(2,-2),Q(7,3),R(11,-1) and S(6,-6)

PQ=√(3-(-2))²+(7-2)²=√25+25=5√2

QR=√(7-11)²+(3-(-1))²=√16+16=4√2

RS=√(11-6)²+(-1-(-6))²=√25+25=5√2

PS=√(2-6)²+(-2-(-6))²=√16+16=4√2

So,PQ=RS and QR=PS

Thus, opposite sides are equal.