Question

Show that points p (2,-2), Q(7,3), R(11,-1) and S (6,-6) are vertices of a parallelogram .​

Answer 1

Answer:

• PQ=
• $5 \sqrt{2}$
• QR=
• $4 \sqrt{2}$
• RS=
• $5 \sqrt{2}$
• PS
• $4 \sqrt{2}$

Step-by-step explanation:

So,PQ=RS and QR=PS

Thus,opposite side are equal.

Hence,the given points form a parallogram