Question

Show that polynomial x^2 + 6x + 10has no zero

Answer 1

x²+6x+10=0

we know that , D =b²-4ac

where D= discriminant

and given:- a=1 , b=6 , and c=10

now putting in the formula that above mentioned

D =(6)²-4×1×10

D=36-40

D=-4

WHERE D=-4<0

THEREFORE , IT HAS NO REAL ROOT OR ZEROS