show that polynomial x3_3x2_x+6 has (x_2) as a factor and leaves remainder 3,when it is divided by (x_3)
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
According to remainder theorem,
x-2=0
x = 2
=> (2)³-3(2)²-2+6
=> 8-3*4-2+6
=> 8-12-2+6
=> 14-14
=> 0
x-3 = 0
x = 3
=> (3)³-3(3)²-3+6
=> 27-3*9-3+6
=> 27-27-3+6
=> 3
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