show that polynomial xsquare +2x+7 has no zeros
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Heya !!!
P(X) = X² + 2X + 7
Here,
A = 1 , B = 2 and C = 7
Discriminant (D) = B² - 4AC
=> (2)² - 4 × 1 × 7
=> 4 - 28
=> -24 is smaller than 0.
Since,
Discriminant of the given equation is smaller than 0 .So the given equation has no real zeroes.
★ HOPE IT WILL HELP YOU ★
P(X) = X² + 2X + 7
Here,
A = 1 , B = 2 and C = 7
Discriminant (D) = B² - 4AC
=> (2)² - 4 × 1 × 7
=> 4 - 28
=> -24 is smaller than 0.
Since,
Discriminant of the given equation is smaller than 0 .So the given equation has no real zeroes.
★ HOPE IT WILL HELP YOU ★
PriyamSahu:
nice answer thanks
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