Question

Show that product of any three consecutive integers is divisible by 3 factorial

Answer 1

Answer:

Step-by-step explanation: simply it is 1,2,3

1+2+3 = 6

6 is divisible by 3

[3 x 2 = 6]

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Answer 2

Answer:

3!=1*2*3=6

In any group of three consecutive integers- one number is divisible by 2 and one is divisible by 3. So their product will be divisible by 2*3=6 which is equal to 3!

Example- the lowest positive integers: 1, 2 & 3