show that quadrilateral abcd with vertices a (0,-2), b (5,1), c(2,6), d (-3,3) is a square
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helo guys its your answer
Step-by-step explanation:
Let A(3, 2), B(0, 5), C(- 3, 2) and D(0, - 1) are the vertices of quadrilateral. Also AC2 = (3 + 3) 2 + (2 – 2)2. AC2 = 36. Or BD2 = (0 – 0)2 + (5 +
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