Show that r+r3+r1-r2=4RcosB
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Proved that r+r3 +r – r2 = 4R
Cos B
Given
To prove that r +r3+ri - r2 = 4R
Cos B
Let us take, r +r3 = 4R
sinC sinA sinb +cosA , cosB) 2( sin
(1)
= 4sin cos 4,B
ri - r2 = 4R sin \frac{C}
(2}}[ sin sin + cos cos ]
= 4r Cos, sin (4-B) (2)
Add the equation (1) and ( 2 ) to get the desired result,
r r3 + r – r2
= 4Rsin cos 4B +
4 Cos, sin (4,B)
Add the equation (1) and ( 2 ) to get the desired result,
r + r3 +ri – r2
= 4Rsin cos4 B +
4cos sin ^z" 2
C = 4Rsin 2 A 2 B 2 + +
= 4 Sin(90 – - 5) B 2
= 4Rsin(90 – 25)
sin (90° - B) = cos B )
4R cos B. =
Hence, proved.
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