Question

show that (r-s)²+2rs=r²+s²​

Answer 1

Step-by-step explanation:

To prove : (r - s)² + 2rs = r² + s²

L.H.S. = (r - s)² + 2rs

Identity : (a - b)² = a² + b² - 2ab

Here, a = r, b = s

→ (r)² + (s)² - 2(r)(s) + 2rs

→ r² + s² - 2rs + 2rs

→ r² + s² = R.H.S.

Hence, proved !!

Answer 2

Answer:

(r-s)²+2rs=r²+s²​

∵ $(a-b)^{2}$ = $a^{2}$ + $b^{2}$ - 2ab

(r-s)² = r² + s²​ - 2rs

⇒ r² + s²​ - 2rs + 2rs = r² + s²​

⇒ r² + s²​  = r² + s²

Hence proved.​

Hope it helps!

Please mark as Brianliest.