Question

show that rms velocity of oxygen molecule is √2 times that of sulfur dioxide molecule at STP​

Answer 1

Hey mate here is ur answer =

$\red{Solution:}$

Formula = rms speed of o2/rms speed of so2= root(mass of so2/mass of o2)

Mass of o2=32 gm/mol

Mass of so2=64 gm/mol

rms of o2/rms of so2 = root (64/32)

rms speed of o2/rms speed of so2 = root 2

hence rms velocity of oxygen molecule is root 2 times that of sulphur dioxide molecule.

hope it helps.

$\red{Thank You}$

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Answer 2

Answer:

Show that rms velocity of an oxygen  molecule is 2 times that of a sulfur  dioxide molecule at S.T.P.