Question

show that root 3 - root 2 / root 3 + root 2 + root 3 + root 2 / root 3 - root 2​

Answer 1

Answer:

$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } = 5 - 2 \sqrt{6} \\ \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = 5 + 2 \sqrt{6} \\ \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3 } + \sqrt{2} } + \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = 10$