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that root 5 - root 7 is irrational
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Answer:
Because in number is given√5-√7,
√5-√7)(√5+√7)
(√5) sq-(√7)sq
5-7
-2
therefore√5-√7is are irrational number
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Answer:
let √5-7 is rational number
let p&q are co-primes
squaring on both sides (s.o.b.s)
(√5-7) square and (p/q) square
(√5-7) and (p/q) will remain
(√5-6/q)and p
transpose -6 to that's side we will get (+6/p)
and transpose q we will get( 6/p_q) √5 is in RHS side so for every integer irrational should be LHS
so assumptions is wrong √5-7 is rational number
HENCE PROVED
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