Question

show that root 6 + root 2 is irrational number ​

Answer 1

Answer:

Step-by-step explanation:

Let √2 + √3 = (a/b) is a rational no.

On squaring both sides , we get

2 + 3  + 2√6 = (a2/b2)

So,5 + 2√6 = (a2/b2) a rational no.

So, 2√6 = (a2/b2) – 5

Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.

So, my contradiction is wrong.

So, (√2 + √3) is an irrational no.

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