Math, asked by dj12387, 1 year ago

show that root of sec ² theeta+ Cosec ²theeta=tantheeta +cottheeta​

Answers

Answered by PraneethK
0

Answer:

LHS =root(sec²þ+cose²þ)

root(1/cos²þ+1/sin²þ)

root(sin²þ+cos²þ/sin²þcos²q)

root(1/sin²þcos²q)

root(sec²þcose²þ)

=root((1+tan²þ)(1+cot²þ))

=root(1+tan²þ+cot²q+tan²þcot²q)

=root(1+tan²þ+cot²þ+1) (tan²qcot²þ=1)

=root(tan²þ+cot²þ+2(1))

=root(tan2þ+cot²þ+2(tanþcotþ)

(again identity)

=root(tanþ+cotþ)²

=tanþ+cotþ

pls mark as brainlest

Answered by adityayadav06050
1

Answer:

hope this will be helpful...

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