show that root3 +2root5 is irrational
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let us take 3+2√3 is a rational
=> 3+2√3 = p/q (where q is not equal to 0 and p and q are co prime numbers)
2√3= p/q-3
2√3= p-3q/q
√3=(p-3q/q)/2
√3=(p-3q/2q) which is a integer
but is we we know √3 is an irrational
3+2√3 is a irrational
=> 3+2√3 = p/q (where q is not equal to 0 and p and q are co prime numbers)
2√3= p/q-3
2√3= p-3q/q
√3=(p-3q/q)/2
√3=(p-3q/2q) which is a integer
but is we we know √3 is an irrational
3+2√3 is a irrational
Answered by
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heya...
let root3 + 2√5 is rational...
therefore they can be written in the form of
p/q..
here √3+2√5 = a/b..
where a;b are co-primes
now √3 +√5 = a/2b
= √3 + √5 = a/2b
but we know that a rational number is not equal to a irrational number..
this contradiction arised due to our incorrect assumption
therefore √3+2√5 is irrational...
let root3 + 2√5 is rational...
therefore they can be written in the form of
p/q..
here √3+2√5 = a/b..
where a;b are co-primes
now √3 +√5 = a/2b
= √3 + √5 = a/2b
but we know that a rational number is not equal to a irrational number..
this contradiction arised due to our incorrect assumption
therefore √3+2√5 is irrational...
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