show that route 1+sinA/1-sinA=secA+tanA
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LHS=1−sinA1+sinA
=1−sinA1+sinA×1+sinA1+sinA
=(1+sinA)(1−sinA)(1+sinA)2
=1−sin2A(1+sinA)2
=cos2A(1+sinA)2
=(cosA1+sinA)2
=cosA1+sinA
=cosA1+cosAsinA
=secA+tan
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