Question

show that scalar product of two non zero peroendicular vector is zero​

Answer 1

Answer:

The scalar product of two non zero perpendicular vectors is zero​

Explanation:

A vector is a physical quantity that has both magnitude and direction.

One of the multiplications of two vectors is named the scalar product

The scalar product of two vectors A and B inclined to an angle $\alpha$ is given by the formula

$A.B=/A//B/cos\alpha$

the scalar product can be zero if,

1. $/A/=0$
2. $/B/=0$
3. $cos\alpha =0$

from the question, it is given that vector A and vector B are non-zero vectors

then the only chance is $cos\alpha =0$

the minimum value of the angle that makes cosine zero is $\alpha =90$

that is the two vectors are perpendicular to each other

Answer 2

Shown that scalar product of two non zero perpendicular vector is zero​

Given:

• Scaler product of two non zero vectors is Zero

To Find:

• Prove That Vectors are perpendicular

Solution:

• Scaler product of two vectors P and Q  is given by:
• | P | | Q | Cosθ
• θ is the angle between vectors P and Q

Step 1:

Equate Scaler Product to Zero

| P | | Q | Cosθ = 0

Step 2:

Non zero Vectors hence  | P | ≠ 0 , | Q | ≠ 0 So Divide both sides by | P | | Q |

Cosθ = 0

Step 3:

Use cos90° = 0 hence

θ = 90°

Angle between vectors is 90 degrees hence they are perpendicular

QED

Hence Proved

Learn More:

Write formula for dot product.If xi + yj, then find its magnitude ...

brainly.in/question/23144792

If vector A = 2i + 3j - k and vector B = 4i + 6j - 2k; where i, j and ka re ...

brainly.in/question/11911828