Question

Show that (sec 0 + cos0 )(sec- cos 0) = tan square 0 + sin 0
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Answer 1

QUESTION :-

Show that :-

(sec Θ + cos Θ)(sec Θ - cos Θ) = tan² Θ + sin² Θ

SOLUTION :-

L.H.S. = (sec Θ + cos Θ)(sec Θ - cos Θ)

= (sec Θ)² - (cos Θ)²

= sec² Θ - cos² Θ

= ( 1 + tan² Θ ) - ( 1 - sin² Θ )

= 1 + tan² Θ - 1 + sin² Θ

= tan² Θ + sin² Θ

= R.H.S.

Hence showed.

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FORMULA USES :-

1. sec² A = 1 + tan² A

2. cos² A=1 - sin² A [°•° sin²A + cos²A=1 ]

3. (A + B) (A - B) = A² - B²

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Hope it helps you..!!

Answer 2

Hence proved..............