Question

show that sec^-1(5/4)+tan^-1(5/12)=cot^-1(33/56)​

Answer 1

tan (a+b)= tan a +tan b/1-tan a tanb

putting a=5/12 and b =4/3

tan (a+b)=5/12+4/3/1-5/12×4/3

tan a+b = 63/36×36/16

tan (a+b) = 63/16

a+b=tan inverse of (63/16)

sin inverse of 5/13+cos inverse of 3/5=tan inverse of 63/16

Hope it helps u

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