Question

show that sec^2+cosec^2=sec^2.cosec^2​

Answer 1

sec²A + cosec²A,

1/cos²A + 1/sin²A,

(sin²A + cos²A)/sin²A.cos²A,

1/(sin²A.cos²A),

1/sin²A × 1/cos²A,

sec²A.cosec²A

Answer 2

Answer:cosec^2 = sec ^ 2 . Cosec ^ 2 - cosec ^ 2

Cosec ^ 2 = çosec ^ 2 ( sec ^ 2 - 1 )

Tan ^ w theta

Step-by-step explanation: