Math, asked by amritvarsha1976, 9 months ago

Show that sec^2 x + cosec^ x is greater than equal to
4.​

Answers

Answered by calgondiago
0

Answer:

Step-by-step explanation:

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Answered by Unni007
1

We know,

  • sec²x = 1 + tan² x
  • cosec²x = 1 + cot²x

So according to question,

sec²x + cosec²x = 2 + tan²x + cot²x

But ,

We know that A.M > G.M

So ,

(tan²x + cot²x)/2  >  √(tan²x.cot²x)

⇒ tan²x + cot²x  >  2 × 1

⇒ tan²x + cot²x  >  2

Now ,

Adding 2 on both sides ,

(1 + tan²x) + (1 + cot²x)  >  2 + 2

⇒ sec²x + cosec²x  >  4

Hence proved !!!!!

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