Question

show that (sec A+tan A ) (1-sin A) = cos A​

Answer 1

Answer:

(sec A + tanA ) ( 1-sinA)

Step-by-step explanation:

= cos A .

Answer 2

Answer:

(secA+tanA)(1-sinA)= cosA substitute secA= 1/cosA

and substitute tanA= sinA/cosA

Step-by-step explanation:

=((1/cosA)+(sinA/cosA))(1-sinA)

=((1+sinA)/cosA)(1-sinA)

=(1^2-sin^2A)/cosA using (a+b)(a-b)=a^2-b^2

=cos^2A/cosA

=cosA

=RHS