Question

Show that sec square x + cosec sq x is greaterthan equal to 4

Answer 1

We know that a + 1/a (eq. 1)is greater than equal to 2

${sec}^{2} x = {tan}^{2} x + 1$
${cosec}^{2} x = {cot}^{2} x + 1$
So,
${sec}^{2} x + {cosec}^{2} x = 2 + {tan}^{2} x + {cot}^{2} x$
From eq. 1 we can say that
${tan}^{2} x + {cot}^{2} x \geqslant 2$
Hence,

${sec}^{2} x + {cosec}^{2} x \geqslant 2 + 2$
So,

${sec}^{2} x + {cosec}^{2} x \geqslant 4$

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Answer 2

Answer:

hey

Step-by-step explanation:

here it is,,,,,,

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