Question

Show that : (sec - tan)^2= 1-sin/ 1+ sin​

Answer 1

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Prove that (secA−tanA)

2

=

1+sinA

1−sinA

Medium

Solution

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LHS=(secA−tanA)

2

=(

cosA

1

−

cosA

sinA

)

2

=

(1−sin

2

A)

(1−sinA)

2

=

(1−sinA)(1+sinA)

(1−sinA)

2

=

1+sinA

1−sinA

=RHS

Hence proved

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Answer 2

Step-by-step explanation:

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