Question

show that (sec

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Answer 1

Here is the answer ! Hope it helps !
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Answer 2

$( sec\theta - tan\theta)^{2} = \frac{1-sin\theta}{1+sin\theta} \\\\LHS\\(\frac{1-sin\theta}{cos\theta} })^{2} \\\\\frac{(1-sin\theta)^{2} }{cos^{2}\theta } \\\\\frac{(1-sin\theta)^{2} }{1-sin^{2}\theta } \\\\\frac{(1-sin\theta)^{2} }{(1-sin\theta)(1+sin\theta)} \\\\\frac{1-sin\theta}{1+sin\theta} \\\\= RHS$