Show that: sec² ∅ x cosec² ∅ = sec² ∅ + cosec² ∅
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L.H.S. =sec2A+cosec2A < /p > < p > < /p > < p > ⇒cos2A1+sin2A1 < /p > < p > < /p > < p > ⇒sin2Acos2Asin2A+cos2A < /p > < p > < /p > < p > ⇒sin2Acos2A1 < /p > < p > < /p > < p > ⇒cosec2Asec2A= R.H.S. < /p > < p > < /p > < p >L.H.S. =sec2A+cosec2A</p><p></p><p>⇒cos2A1+sin2A1</p><p></p><p>⇒sin2Acos2Asin2A+cos2A</p><p></p><p>⇒sin2Acos2A1</p><p></p><p>⇒cosec2Asec2A= R.H.S.</p><p></p><p>
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