Show that: sec² ∅ x cosec² ∅ = sec² ∅ + cosec² ∅ ppz want ans urgent don't spam plz
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Explanation:
here thetha = a
RHS = sec²a + cosec²a
1/COS²a + 1/sin²a
sin²a + cos²a/sin²a × cos²a [ LCM]
1 / sin²a× cos²a [ sin²a + cos²a = 1]
sec²a×cosec²a
HENCE PROVED
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Answered by
0
Answer:
okay
Explanation:
Sec square teta × cosec square teta is equal to sec square teta + cosec square teta.
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