Question

Show that
Secx-tanx+1/secx+tanx+1=1-sinx/cosx

Answer 1

Answer:

$\red{ \frac{ \sec( x ) - \tan( x) + 1}{ \sec( x) + \tan( x ) + 1 } = \frac{ 1 - \sin( x ) }{ \cos( x ) } }$

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