Show that sequence (3n-7) is an A.P. Find its term and the common difference.
Answers
Answered by
6
Answer:
ap = -4,-1,2
d= -3
Step-by-step explanation:
for n=1
3n-7= 3(1)-7= -4
=>a= -4
for n =2
3n-7 = 3(2)-7 = -1
=> A2 = -1
for n= 3
3n=3(3)-7 =2
A3= 2
=>ap - -4,-1,2....
d= (-4)-(-1)
-4+1
-3
Answered by
0
Answer:
ghxnd
Step-by-step explanation:
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