Math, asked by shreyasakhare, 11 months ago

Show that sequence (3n-7) is an A.P. Find its term and the common difference.​

Answers

Answered by siddhiiiiiiiii
6

Answer:

ap = -4,-1,2

d= -3

Step-by-step explanation:

for n=1

3n-7= 3(1)-7= -4

=>a= -4

for n =2

3n-7 = 3(2)-7 = -1

=> A2 = -1

for n= 3

3n=3(3)-7 =2

A3= 2

=>ap - -4,-1,2....

d= (-4)-(-1)

-4+1

-3

Answered by valentinaasamoah64
0

Answer:

ghxnd

Step-by-step explanation:

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