Question

Show that sequence 7,2,-3,-8 is an ap... find its general term​

Answer 1

Hope that you will find it useful :)

*sorry for the bad handwriting and crossings

Answer 2

Step-by-step explanation:

Given:

7,2,-3,-8

To find:Show that sequence is an A.P., find its general term.

Solution:

To find the sequence is an A.P., check for common difference of consecutive term,if it is same then given sequence is an A.P.

$d = 2 - 7 \\ \\ d = - 5...eq1$

$d = - 3 - 2 \\ \\ d = - 5...eq2$

Taking last two terms

$d = - 8 + 3 \\ \\ d = - 5 ...eq3$

From equation 1,2 and 3

It is clear that given sequence is an A.P.

Finding general term:

General term of A.P.

$\bold{a_n = a + (n - 1)d}$

Here

$a = 7 \\ \\ d = - 5 \\ \\ a_n = 7 + (n - 1)( - 5) \\ \\ a_n = 7 - 5n + 5 \\ \\\bold{ a_n = 12 - 5n }$

Hope it helps you.

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