Show that sequence Defined by An=5n+ 1 is an A.P., also find its common difference.
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The defined Sequence is an A.P with common Difference 5
Step-by-step explanation:
An = 5n + 1
Suppose n = 1
A1 = 5(1) + 1 = 5 + 1 = 6
Suppose n = 2
A2 = 5(2) + 1 = 10 + 1 = 11
Suppose n = 3
A3 = 5(3) + 1 = 15 + 1 = 16
Now if the defined sequence is an A.P then the common difference should be same.
D1 = A2 - A1 = 11 - 6 = 5
D2= A3 - A2 = 16 - 11 = 5
As D1= D2, the defined Sequence is an A.P with common Difference 5
lopamudra15:
thank u
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