show that set of natural no. is order complete
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An ordered set is said to be order complete, if every non-empty subset having an upper bound, also has a least upper bound. ... Now the least element of a subset is obviously its greatest lower bound and the set N of all natural numbers satisfies the property that every non-empty subset of it has a greatest lower bound.
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An ordered set is said to be order complete, if every non-empty subset having an upper bound, also has a least upper bound. ... Now the least element of a subset is obviously its greatest lower bound and the set N of all natural numbers satisfies the property that every non-empty subset of it has a greatest lower bound.
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