Question

show that
Show that (a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)​

Answer 1

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Answer 2

Answer:

0

Step-by-step explanation:

Given,

(a-b)(a+b)+(b+c)(b-c)+(c-a)(c+a)

= a^2-b^2+b^2-c^2+c^2-a^2

then everything get cancel

= 0.