Question

show that sigma a cot A = 2(R+r)​

Answer 1

Step-by-step explanation:

acotA+bcotB+ccotC =asinAcosA+bsinBcosB+csinCcosC Using sine rule sinAa=sinBb=sinCc=2R we have =2 R(cosA+cosB+cosC)

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Answer 2

Answer:

This is the answer

Step-by-step explanation:

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