Show that sin 10 + sin 20 + sin 40 + sin 50 = sin 70 + sin 80
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sin 10° + sin20° + sin40° + sin50° = sin70° + sin80°
we will first solve
L.H.S. = 2sin15cos5+2sin45cos5 [ using sin C+sin D= 2sin C+D/2 cos C-D/2 for sin10+sin20 & sin40+sin50]
= 2cos5 (sin15+sin45)
= 2cos5 (2sin30cos15) [ using sin C+sin D= 2sin C+D/2 cos C-D/2 ]
= 2cos5 (2 x 1/2 x cos15)
= 2cos5 cos15
Now its the turn for RHS
R.H.S. = sin70+sin80
= 2sin75cos5 [ using sin C+sin D= 2sin C+D/2 cos C-D/2 ]
sin75 = sin(90-15) = cos 15
L.H.S = 2cos5 cos15
R.H.S. = 2cos15 cos5 [ since, sin75 = cos15 ]
Got it
sin 10° + sin20° + sin40° + sin50° = sin70° + sin80°
we will first solve
L.H.S. = 2sin15cos5+2sin45cos5 [ using sin C+sin D= 2sin C+D/2 cos C-D/2 for sin10+sin20 & sin40+sin50]
= 2cos5 (sin15+sin45)
= 2cos5 (2sin30cos15) [ using sin C+sin D= 2sin C+D/2 cos C-D/2 ]
= 2cos5 (2 x 1/2 x cos15)
= 2cos5 cos15
Now its the turn for RHS
R.H.S. = sin70+sin80
= 2sin75cos5 [ using sin C+sin D= 2sin C+D/2 cos C-D/2 ]
sin75 = sin(90-15) = cos 15
L.H.S = 2cos5 cos15
R.H.S. = 2cos15 cos5 [ since, sin75 = cos15 ]
Got it
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