SHOW THAT SIN 100 DEGREE-SIN 10 DEGREE IS POSITIVE
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Answered by
50
As per the given expression will be write as Sin 100 - sin 10
=sin(90+10)- Sin 10
=sin90 cos10- cos90sin10-Sin 10
√2(1/√2 cos 10 -1/√2 sin10)
√2 sin〖(45〗-10)
√2 sin35
We are clear that first quadrant sing is positive so sin 35 >0
Therefore result is sin 100-sin 10=√2sin 35>0 hence it is positive.
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Answer:
refer the attachment!!!!
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