Math, asked by TheLifeRacer, 10 months ago

SHOW THAT sin^-2√3/3 + sin^-1/3 = π/2 ​

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Answered by Anonymous
0

Answer:

The given inverse function is in sine

If you are allowed to use the formula of sin^-a+sin^-b then use it but i think u aren't so the alternative would be

to make two right angled triangles and find tan^-

i think after finding tan^- u are smart enough to proceed using

tan^-a+tan^-b=tan^-(a+b/1-ab)

which will come out to be infinity

All the best.

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Answered by aishu0105
3

Answer:

The given inverse function is in sine

If you are allowed to use the formula of sin^-a+sin^-b then use it but i think u aren't so the alternative would be

to make two right angled triangles and find tan^-

i think after finding tan^- u are smart enough to proceed using

tan^-a+tan^-b=tan^-(a+b/1-ab)

which will come out to be infinity

hope it helps u

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